TNPSC CESE Recruitment 2019 announced-Here are details

TNPSC has come up with vacancies for various posts under Combined Engineering Services Examination (CESE) 2019.

TNPSC CESE Recruitment 2019 announced-Here are details
TNPSC Recruitment 2019, Apply for 7038 TNPSC Latest Jobs @ tnpsc.gov.in

Tamil Nadu Public Service Commission (TNPSC) has announced vacancies for different posts under the Combined Engineering Services Examination 2019 (CESE 2019). The posts are Assistant Electrical Inspector, Assistant Engineer (AE) and Junior Architect.

There are in total 481 vacancies for the post.TNPSC has asked the candidates to apply online and they can register themselves by visiting tnpscexams.in.

Application date starts from 29th May 2019 and the last date to apply is 28th June 2019. Candidates have to download the TNPSC CESE 2019 exam notification through the official website of TNPSC official which is tnpsc.gov.in. You need to submit the application online till 28.06.2019.

Candidates should possess an engineering degree from a recognized institute in the required discipline. Also, the applicant should fall under the prescribed age limitations. Apart from that, the candidate needs to have a proper hold over Tamil.

TNPSC Selection process:

It will conduct Combined Engineering Services written Examination and interview.

The date for the Combined Engineering Services written Examination: 10.08.2019 (FN & AN)

It is going to take place at 32 districts in Tamil Nadu.

TNPSC recruitment fee is paid through either online mode or offline mode.

Last date for fee payment:  30.06.2019. Candidate can pay through State Bank of India or HDFC Bank.

Pay Scales for different posts:

Assistant Electrical Inspector is paid ₹ 15600 - 39100 + GP ₹ 5400/- pm (Level 22).

 â‚¹ 9300 - 34800 + GP ₹ 5100/- p.m. is for the remaining posts

Application Fee includes ₹ 150/- for One-time Registration Fee and ₹ 200/- for Examination Fee.

SC, ST, PWD, MBS, BC and Ex-Servicemen categories are exempt for fee payment.